Radio carbon dating is done by estimating in a specimen:

the amount of ordinary carbon still present

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the amount of radio carbon still present

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the ratio of amount of

_{6}^{14} C

_{6}^{12} C

still present

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the ratio of amount of

_{6}^{12} C

_{6}^{28} C

still present

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Solution

The correct option is A the ratio of amount of $_{6}^{14} C$ to $_{6}^{12} C$ still present
Radio carbon dating is done by using the ratio of $^{14} C t o^{12} C a s : \frac{ln \frac{^{12} C}{^{14} C}}{k} = t$

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Radio carbon dating is done by estimating in a specimen:

The correct option is A the ratio of amount of 146C to 126C still presentRadio carbon dating is done by using the ratio of 14Cto12Cas:ln12C14Ck=t

The correct option is A the ratio of amount of $_{6}^{14} C$ to $_{6}^{12} C$ still present
Radio carbon dating is done by using the ratio of $^{14} C t o^{12} C a s : \frac{ln \frac{^{12} C}{^{14} C}}{k} = t$