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Question

Radioactive disintegration of 22688Ra takes place in the following manner into RaC,
Raα−−−−Rnα−−−−RaAα−−−−RaBβ−−−−RaC
Determine mass number and atomic number of RaC.

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Solution

Parent element is 22688Ra
Atomic mass =226
Atomic number =88
RaC is formed after the emission of 3 alpha particles. Mass of 3 alpha particles =3×4=12
So, atomic mass of RaC=(22612)=214
With emission of one α-particle, atomic number is decreasd by 2 and with the emission of one β-particle, atomic number is increased by 1.
So, Atomic number of RaC=88(3×2)+1=83

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