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Radioactive t...

Question

Radioactive transmitter transmits at 830 kHz. At a certain distance from transmitter, magnetic field has amplitude 4.82x10^-11 T. Electric field and wavelength are:

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Solution

Dear Student,
$B_{0} = 4.82 * 10^{- 11} E_{0} = B_{0} C = 4.82 * 10^{- 11} * 3 * 10^{8} = 0.0146 w a v e l e n g t h = C f = \frac{3 * 10^{8}}{830000} = \frac{30000}{83} = 361.445 m R e g a r d s$
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