Question

Radiolysis of water yields hydrogen according to the reaction:
$2H_{2}O⟶H_2+H_2{O}_2$

Calculate the value of hydrogen produced per hour in a 200 kW reactor. The yield of hydrogen is 1.7 molecules per 100 eV of energy absorbed.

• A. 2846.5 L at STP
• B. 4546.5 L at STP
• C. 3246.5 L at STP
• D. None of these

Answer 1

Answer: (A)

2846.5 L at STP

Power of reactor=200kW

Energy absorbed in 1 second=200kJ

Energy absorbed in 1 hour $=200\times 3,600=7.2\times {10}^{5}kJ$

$=\frac{7.2\times {10}^5\times 1000}{1.6\times {10}^{-19}}eV=4.5\times {10}^{27}eV$

No. of molecules of hydrogen produced $=\frac{4.5\times {10}^{27}\times 1.7}{100}=7.65\times {10}^{25}$

Moles of $H_2$ gas produced $\frac{7.65\times {10}^{25}}{6.023\times {10}^{23}}=127.0131moles$

Volume released at STP (using PV=nRT)

$=\frac{127.0131\times 0.0821\times 273}{1}L$

$=2846.7L\cong 2846.5L$

Thus correct option is A.