Radius of $3^{r d}$ Bohr orbit is ___________.

6.529 o A

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2.116 o A

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4.761 o A

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8.464 o A

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Solution

The correct option is C $4.761 o A$
Radius of Bohr's orbit $=$ Radius of hydrogen atom
Radius of $n^{t h}$ orbit of an atom is given by the following formula.
$r_{n} = \frac{0.529 n^{2}}{Z} o A$
$∴ r_{3} = \frac{0.529 \times 3^{2}}{1} o A$ $= 4.761 o A$

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