Radius of $3^{r d}$ Bohr orbit of hydrogen atom is:

6.59 A^{o}

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2.116 A^{o}

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4.761 A^{o}

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8.464 A^{o}

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Solution

The correct option is C $4.761 A^{o}$
The radius of an orbit is given by,

$r = \frac{n^{2} h^{2}}{4 π^{2} m Z e^{2}}$

Substituting the values of $h, m, z = 1$ for hydrogen and the electron charge army be calculated as

$r = 0.529 \times n^{2} A^{0}$

For $n = 3$

$r = 4.761 A^{0}$

Hence, the correct option is $C$

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