Radius of a circle is doubled. What will be the ratio between the area of the new circle and the area of the original circle?

2:3

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4:8

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4:1

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5:3

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Solution

The correct option is C
4:1

Let the radius be $r$ , then new radius = $2 r$

Area1 = $π r^{2}$ , New Area = $π (2 r)^{2}$

$∴$ $\frac{π (2 r)^{2}}{π r^{2}}$ = $\frac{4}{1}$ = 4: 1

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Radius of a circle is doubled. What will be the ratio of areas of the new circle to the area of the given circle?

Question 3

A circle of maximum possible size is cut from a square sheet of board. Subsequently, a square of maximum possible size is cut from the resultant circle. What will be the area of the final square?
(a) $\frac{3}{4}$ of original square (b) $\frac{1}{2}$ of original square
(c) $\frac{1}{4}$ of original square (d) $\frac{2}{3}$ of original square

Q. Question 30

If the radius of a circle is increased to twice its original length, how much will the area of the circle increase?

(a) 1.4 times
(b) 2 times
(c) 3 times
(d) 4 times

Q. The area of a circle is increased by 22 cm² when its radius is increased by 1 cm.
The original radius of the circle is

(a) 6 cm (b) 3 cm (c) 4 cm (d) 3.5 cm

Q. The ratio of circumference of

2

circle is

3 : 4

then what is the ratio of the corresponding areas.

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Radius of a circle is doubled. What will be the ratio between the area of the new circle and the area of the original circle?

The correct option is C 4:1 Let the radius be r , then new radius = 2r Area1 = πr2 , New Area = π(2r)2 ∴ π(2r)2πr2 = 41 = 4: 1

The correct option is C
4:1

Let the radius be $r$ , then new radius = $2 r$

Area1 = $π r^{2}$ , New Area = $π (2 r)^{2}$

$∴$ $\frac{π (2 r)^{2}}{π r^{2}}$ = $\frac{4}{1}$ = 4: 1