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Question

Radius of a circle with center O is $$ 41 $$ units . length of a chord PQ is 80 units ,Find the distance of the chord from the  center of the circle.


Solution

Given that, 

6

Radius of circle (OA) = 41cm

Chord (AB) = 80cm

Draw OCAB

We know that

The perpendicular from centre to chord bisects the chord

AC=BC=802=40cm

Now in ΔOCA, by Pythagoras theorem

AC+ OC= OA2

=>402 + OC2 = 412

=>1600 + OC2 = 1681

=>OC2 = 81

=> OC2 = 81

=>OC = 81

=>OC = 9cm


Maths

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