Radius of circle touching y-axis at point P(0,2)and circle $x^{2} + y^{2} = 16$ internally

\frac{5}{2}

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\frac{3}{2}

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\frac{5}{4}

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Solution

The correct option is D 1
$D i a m e t e r of circle touch y-axis at P(0,2) and circle x^{2} + y^{2} = 16$
$W h e n circle touches internally$
$| c_{1} c_{2} | = | r_{1} - r_{2} | [w h e r e r_{1} = 4, r_{2} = 2]$
$F r o m t h e f i g u r e we can say that$
$Diameter of circle is 2$
$∴$ Radius of circle touching $y - a x i s$ at point $P (0, 2)$ is $\frac{D i a m e t e r}{2} = \frac{2}{2} = 1$

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