Radius of circle(x–5)(x–1) + (y – 7)(y – 4) = 0 is

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Solution

The correct option is C
Extremities of diameter are (5, 7) and (1, 4) and radius is half of the distance between them
$= \frac{1}{2} \sqrt{(4)^{2} + (3)^{2}} = \frac{5}{2}$

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