Radius of curvature of Plano-Convex lens is 10 cm and Focal length of lens is 30 cm. Then refractive index of material of lens is:-

1.65

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1.55

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1.33

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1.25

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Solution

The correct option is C $1.33$
$R_{1} = \infty R_{2} = - 10 c m$
$\begin{matrix} We know, \frac{1}{f} = (n - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) \Rightarrow \frac{1}{30} = (n - 1) (\frac{1}{10}) . \Rightarrow n = 4 / 3 = 1.333 \end{matrix}$

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Radius of curvature of Plano-Convex lens is 10 cm and Focal length of lens is 30 cm. Then refractive index of material of lens is:-

The correct option is C 1.33R1=∞R2=−10cm We know, 1f=(n−1)(1R1−1R2)⇒130=(n−1)(110).⇒n=4/3=1.333

The correct option is C $1.33$
$R_{1} = \infty R_{2} = - 10 c m$
$\begin{matrix} We know, \frac{1}{f} = (n - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) \Rightarrow \frac{1}{30} = (n - 1) (\frac{1}{10}) . \Rightarrow n = 4 / 3 = 1.333 \end{matrix}$