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Question

Radius of gyration of a thin uniform rod of mass M length L about an axis perpendicular to it at one of its ends is:

A
L
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B
L/2
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C
L/2(3)
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D
L/(3)
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Solution

The correct option is D L/(3)
The moment of inertia of a rod of mass m about an axis perpendicular to it at one of its ends is given by I=ML2/3. Comparing this with the general equation for the moment of inertia, we get, I=MK2, K is the radius of gyration, we get K=L/3
The correct options is option d

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