Question

Radius of the circle ${(x-2)}^2+{(y-3)}^2={\left(5\sqrt{5}\right)}^2$ is:

• A. $5\sqrt{5}$
• B. $5\sqrt{1}0$
• C. $10\sqrt{2}$
• D. $\sqrt{210}$

Answer 1

The correct option is A $5\sqrt{5}$

Given equation is

${(x-2)}^2+{(y-3)}^2={\left(5\sqrt{5}\right)}^2$ ….(1)

Compare of equation(1) with

${(x-x_1)}^2+{(y-y_1)}^2=a^2$

We get ,

$a=5\sqrt{5}$