Radius of the circle x2-y2-2 x cos-2 y sin-8-0- isA- -10B- 1C- 3D- 2 -3

The correct option is C 3R=√(cos^2 θ + sin^2 θ + 8) = 3 ...

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Obtaining Centre and Radius of a Circle from General Equation of a Circle

Radius of the...

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Radius of the circle $x^{2} + y^{2} + 2 x c o s θ + 2 y s i n θ - 8 = 0,$ is

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2 \sqrt{3}

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\sqrt{10}

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x^{2} + y^{2} + 2 x c o s θ + 2 y s i n θ - 8 = 0,

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x^{2} + y^{2} + 2 x + 8 y + 8 = 0

The equation of a circle of radius 1 touching the circles $x^{2} + y^{2} - 2 | x | = 0$ is

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