Radius of the cricket ground is $70$ metre. To make boundary, a rope is to be fixed surrounding it. If cost of fixing the rope of $1$ metre is $R s . 20$ , then what is the total cost to fix the rope on boundary?

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Solution

Radius of cricket ground=70m

Perimeter of ground= $2 π r = 2 \times 3.14 \times 70 = 440 m^{2}$

Cost =area $\times$ rate=440 $\times$ 20=Rs 8800

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Radius of the cricket ground is 70 metre. To make boundary, a rope is to be fixed surrounding it. If cost of fixing the rope of 1 metre is Rs.20, then what is the total cost to fix the rope on boundary?

Radius of cricket ground=70mPerimeter of ground=2πr=2×3.14×70=440m2Cost =area× rate=440× 20=Rs 8800

Radius of the cricket ground is $70$ metre. To make boundary, a rope is to be fixed surrounding it. If cost of fixing the rope of $1$ metre is $R s . 20$ , then what is the total cost to fix the rope on boundary?

Radius of cricket ground=70m

Perimeter of ground= $2 π r = 2 \times 3.14 \times 70 = 440 m^{2}$

Cost =area $\times$ rate=440 $\times$ 20=Rs 8800