Question

Radon-222 decays to polonium-218. The correct reactions for following decay process is:

• A. ${}_{86}^{222}Rn{⟶}_{84}^{218}Po{+}_2^{4}He$
• B. ${}_{86}^{222}Rn{⟶}_{84}^{218}Po{+}_3^{4}He$
• C. ${}_{86}^{222}Rn{⟶}_{84}^{218}Po{+}_2^{3}He$
• D. None of these

Answer 1

The correct option is A ${}_{86}^{222}Rn{⟶}_{84}^{218}Po{+}_2^{4}He$

For balanced reaction, mass and charge of both side should be equal.

${}_{86}^{222}Rn{⟶}_{84}^{218}Po{+}_2^{4}He$

m $222$ $218+4=222$

e $86$ $84+2=86$