MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Gamma Decay

Radon decays ...

Question

Radon decays to polonium by emitting alpha particles as shown by the following equation: $_{y}^{x} R n \to_{86}^{218} P o + α$ . What are the values of x and y?

Open in App

Solution

$_{x} {R n}^{y} \to_{86} {P o}^{218} +_{2} α^{4} x = 86 + 2 = 88 y = 218 + 4 = 222 S o, x = 88 a n d y = 222$

Suggest Corrections

thumbs-up

0

Similar questions

Find the resulting isotope when Polonium-218 decays, it emits a beta particle, followed by an

α

Q. When polonium-218 decays, it emits a beta particle followed by an alpha particle. The resulting isotope is :

X

α

-decay and another nuclide

Y

β^{-}

-decay. Which of the following statements are correct?
1. The

β

-particles emitted by

Y

may have widely different speeds.
2. The

α

-particles emitted by

X

may have widely different speeds.
3. The

α

-particles emitted by

X

will have almost same speed.
4. The

β

-particles emitted by

Y

will have the same speed.

Q. Initially, the nucleus of

Radium - 226

is at rest. It decays by emitting an

α -

particle, and thus the nucleus of

Radon

is created. The released energy during the decay is

4.87 MeV

, which appears as the kinetic energy of the two resulted particles. The kinetic energy of

α -

Radon

nucleus are respectively.

[m_{α} = 4.002 u, m_{Rn} = 222.017 u]

Q. Radon-222 decays to polonium-218. The correct reactions for following decay process is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Types of Radioactive Decays

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon