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Byju's Answer
Standard XII
Chemistry
Gamma Decay
Radon decays ...
Question
Radon decays to polonium by emitting alpha particles as shown by the following equation:
x
y
R
n
→
218
86
P
o
+
α
. What are the values of x and y?
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Solution
x
R
n
y
→
86
P
o
218
+
2
α
4
x
=
86
+
2
=
88
y
=
218
+
4
=
222
S
o
,
x
=
88
a
n
d
y
=
222
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Similar questions
Q.
Find the resulting isotope when P
olonium-218 decays, it emits a beta particle, followed by an
α
-particle ?
Q.
When polonium-218 decays, it emits a beta particle followed by an alpha particle. The resulting isotope is :
Q.
The nuclide
X
undergoes
α
-decay and another nuclide
Y
,
β
−
-decay. Which of the following statements are correct?
1. The
β
-particles emitted by
Y
may have widely different speeds.
2. The
α
-particles emitted by
X
may have widely different speeds.
3. The
α
-particles emitted by
X
will have almost same speed.
4. The
β
-particles emitted by
Y
will have the same speed.
Q.
Initially, the nucleus of
Radium
−
226
is at rest. It decays by emitting an
α
−
particle, and thus the nucleus of
Radon
is created. The released energy during the decay is
4.87
MeV
, which appears as the kinetic energy of the two resulted particles. The kinetic energy of
α
−
particle &
Radon
nucleus are respectively.
[
m
α
=
4.002
u
,
m
Rn
=
222.017
u
]
Q.
Radon-222 decays to polonium-218. The correct reactions for following decay process is:
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