Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet required to make the tube, if the length of the tube is 1 m and the base radius is 3.5 cm? (Take $π = \frac{22}{7}$ )

2200 m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

220 m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2200 cm²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

220 cm²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
2200 cm²

Curved surface area of cylindrical tube = 2πrh = $2 \times \frac{22}{7} \times 3.5 \times 100$ [1 m = 100 cm]
= 2200 $c m^{2}$ .

Suggest Corrections

Similar questions

Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take π=22/7)

Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet he needs to make the tube if the tube has a length of 1m and base radius of 3.5cm? ( $π = \frac{22}{7}$ )

Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take π=22/7) [3 MARKS]

Raghu needs to make a cylindrical aluminum tube. What will be the area of the aluminum sheet required to make the tube, if the length and radius of the tube should be 1 $m$ and 3.5 $c m$ respectively [Top and bottom of the tube are of another material]?

( $u s e π = \frac{22}{7}$ )

Join BYJU'S Learning Program

Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet required to make the tube, if the length of the tube is 1 m and the base radius is 3.5 cm? (Take π=227)

The correct option is C 2200 cm2 Curved surface area of cylindrical tube = 2πrh = 2×227×3.5×100 [1 m = 100 cm] = 2200 cm2.

Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet required to make the tube, if the length of the tube is 1 m and the base radius is 3.5 cm? (Take $π = \frac{22}{7}$ )

The correct option is C
2200 cm²

Curved surface area of cylindrical tube = 2πrh = $2 \times \frac{22}{7} \times 3.5 \times 100$ [1 m = 100 cm]
= 2200 $c m^{2}$ .