Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take $π = \frac{22}{/} 7$ )

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Solution

$r = 3.5 c m, h = 1 m = 100 c m$

Area of Aluminium sheet required = curved surface area of the tube

$= 2 π r h$

$= 2 \times \frac{22}{7} \times 3.5 \times 100$

$= 2200 {c m}^{2}$

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Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet he needs to make the tube, if the tube has length of 1m and base radius of 3.5cm? (Take π = $\frac{22}{7}$ )

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Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take π=22/7)

r=3.5cm,h=1m=100cm Area of Aluminium sheet required = curved surface area of the tube =2πrh =2×227×3.5×100 =2200cm2

Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take $π = \frac{22}{/} 7$ )

$r = 3.5 c m, h = 1 m = 100 c m$

Area of Aluminium sheet required = curved surface area of the tube

$= 2 π r h$

$= 2 \times \frac{22}{7} \times 3.5 \times 100$

$= 2200 {c m}^{2}$