Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take π=22/7) [3 MARKS]

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Solution

Concept: 1 Mark
Formula: 1 Mark
Application: 1 Mark

$r = 3.5 c m, h = 1 m = 100 c m$

Area of Aluminium sheet required = curved surface area of the tube

$= 2 π r h$

$= 2 \times \frac{22}{7} \times 3.5 \times 100$

$= 2200 {c m}^{2}$

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Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet he needs to make the tube if the tube has a length of 1m and base radius of 3.5cm? ( $π = \frac{22}{7}$ )

Raghu had to make a cylindrical aluminium tube. What is the area of the aluminium sheet required to make the tube, if the length of the tube is 1 m and the base radius is 3.5 cm? (Take $π = \frac{22}{7}$ )

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Raghu had to make a cylindrical tube with an aluminium cover. What is the area of the aluminium sheet he needs to cover the tube if the tube has a length of 1m and base radius 3.5cm? (Take π=22/7) [3 MARKS]

Concept: 1 Mark Formula: 1 Mark Application: 1 Mark r=3.5cm,h=1m=100cm Area of Aluminium sheet required = curved surface area of the tube =2πrh =2×227×3.5×100 =2200cm2

Concept: 1 Mark
Formula: 1 Mark
Application: 1 Mark

$r = 3.5 c m, h = 1 m = 100 c m$

Area of Aluminium sheet required = curved surface area of the tube

$= 2 π r h$

$= 2 \times \frac{22}{7} \times 3.5 \times 100$

$= 2200 {c m}^{2}$