Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are $10 c m$ and $7 c m$ respectively. The area of aluminium sheet required to make the cone is
[Use $π = \frac{22}{7}$ ]

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Solution

The correct option is D

Given: radius, $r = 7 m$ , and slant height, $l = 10 m$

Area of the aluminium cone $=$ Total surface area $= π r (l + r)$

$= \frac{22}{7} \times 7 (10 + 7)$

$= 374 {c m}^{2}$

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Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are 10 cm and 7 cm respectively. The area of aluminium sheet required to make the cone is ___ $c m^{2}$
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(π = \frac{22}{7})

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Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are 10 cm and 7 cm respectively. The area of aluminium sheet required to make the cone is [Use π=227]

The correct option is D Given: radius, r=7 m, and slant height, l=10 m Area of the aluminium cone = Total surface area =πr(l+r) =227×7(10+7) =374 cm2

Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are $10 c m$ and $7 c m$ respectively. The area of aluminium sheet required to make the cone is
[Use $π = \frac{22}{7}$ ]

The correct option is D

Given: radius, $r = 7 m$ , and slant height, $l = 10 m$

Area of the aluminium cone $=$ Total surface area $= π r (l + r)$

$= \frac{22}{7} \times 7 (10 + 7)$

$= 374 {c m}^{2}$