Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are 10 cm and 7 cm respectively. The area of aluminium sheet required to make the cone is ___ $c m^{2}$
(Use $π = 3.14$ )

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Solution

Given r=7 m , l=10m

Area of the aluminium cone= Total surface area $= π r (l + r)$

$= \frac{22}{7} \times 7 (10 + 7)$

$= 374 {c m}^{2}$

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Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are $10 c m$ and $7 c m$ respectively. The area of aluminium sheet required to make the cone is
[Use $π = \frac{22}{7}$ ]

Find the area of metal sheet required in making a closed hollow cone of base radius 7 cm and height 24 cm.

Q. The radius and slant height of a cone are

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respectively. Find its curved surface area.

(π = \frac{22}{7})

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Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are 10 cm and 7 cm respectively. The area of aluminium sheet required to make the cone is ___ cm2 (Use π=3.14)

Given r=7 m , l=10m Area of the aluminium cone= Total surface area=πr(l+r) =227×7(10+7) =374cm2

Raghu wants to make a closed aluminium cone for his science project. The slant height and radius of the cone are 10 cm and 7 cm respectively. The area of aluminium sheet required to make the cone is ___ $c m^{2}$
(Use $π = 3.14$ )

Given r=7 m , l=10m

Area of the aluminium cone= Total surface area $= π r (l + r)$

$= \frac{22}{7} \times 7 (10 + 7)$

$= 374 {c m}^{2}$