Rahim tosses two different coins simultaneously. Find the probability of getting at least one tail.

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Solution

Rahim tosses two coins simultaneously. The sample space of the experiment is {HH,HT, TH and TT}.
Total number of outcomes = 4
Outcomes in favour of getting at least one tail on tossing the two coins = {HT, TH, TT}
Number of outcomes in favour of getting at least one tail = 3
$∴$ Probability of getting at least one tail on tossing the two coins
$= \frac{N u m b e r o f f a v o u r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s} = \frac{3}{4}$

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