Rahul forgot to add the reaction mixture to the round-bottomed flask at 27 degrees celsius but instead, he placed the flask on the flame. After a lapse of time, he realized his mistake and using a pyrometer he found the temperature of the flask was 477 degrees Celcius. What fraction of air would have been expelled out?
Step 1: Given data
Step: 2 Introducing the formula :
Charles law states that "When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion".
According to Charles law equation: V ∝ T
The mathematical expression of Charles law can be expressed as follows for comparing the same material under two different sets of conditions:
Where V1 is the initial volume of the system.
V2 is the final volume of the system.
T1 is the initial temperature of the system in Kelvin.
T2 is the final temperature of the system in Kelvin.
Step: 3 Putting the values in the above-mentioned equation
The fraction of air expelled out
=
Therefore, the volume of air that was expelled out is