Rahul's dad was seeing the plan for their new house, the outline of the house is shown in the figure,
Rahul's Dad asked him to find the value of "x" if the perimeter of the outline is 101 m.
x is equal to
10
The perimeter of the outline is the sum of the length of all the sides.
Perimeter = (x+2)+(2x+1)+(2x+10)+(x+2)+(x+3)+(x+3)
Group the variable and numbers,
⇒ (x+2x+2x+x+x+x)+(2+1+10+2+3+3)=(8x)+(21)
Given that, perimeter is equal to 101 m
⇒ 8x+21=101
Subtract 21 from both sides give,
⇒8x+21−21=101−21
⇒8x=80
Divide both sides by 8,
⇒8x8=808
⇒x=10