Question

Rahul was told by his teacher to Calculate mass of the following :
I. 0.5 mole of $N_2$ gas
II. 0.5 mole of N atoms
III. $3.011\times {10}^{23}$ number of N atoms
IV. $6.023\times {10}^{23}$ number of $N_2$ moecules
He calculated the mass as I = x g, II = y g, III = z g, IV = w g
Which relation is correct among these ?

• A. x = y = z = w
• B. x/2 = y = z = w/4
• C. x = 2y = z = 4w
• D. x = y = z/2 = w/4

Answer 1

Answer: (B)

x/2 = y = z = w/4

0.5 moles of $N_2$ weights 14g.
0.5 moles of N atoms weights 7g.
$3.011\times {10}^{23}$ number of N atoms weights 7g.
$6.023\times {10}^{23}$ number of $N_2$ moecules weights 28g.
Hence the relation is $x/2=y=z=w/4$