Question

Raindrops falling vertically down appear to fall at ${45}^{\circ }$ on a man when he moves horizontally at $5m{s}^{-1}$ and ${30}^{\circ }$ with vertical when he reduces his speed. His new speed is (in $m{s}^{-1}$)

• A. $\frac{5}{\sqrt{3}}$
• B. $\frac{5}{\sqrt{2}}$
• C. $\sqrt{\frac{25}{14}}$
• D. $\frac{3}{5}$

Answer 1

The correct option is A $\frac{5}{\sqrt{3}}$

$V=5m/s$
as $Tan45=1=\frac{-5}{v}$
So, $Tan{30}^{\circ }=\frac{v^1}{5}$
$v^1=\frac{5}{\sqrt{3}}$