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Byju's Answer

Standard IX

Physics

Derivation of Position-Velocity Relation by Graphical Method

Raj can uploa...

Question

Raj can upload $n$ videos of approximately $4.5$ gigabytes in size each on cloud between $5 : 00$ PM and $9 : 00$ PM daily, with speed of $12$ megabytes per second. What is the maximum value of $n$ per day? ( $1$ gigabyte $= 1024$ megabytes)

2

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37

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38

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682

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Solution

The correct option is D $37$
To upload a video of $4.5$ GB with a speed of $12 M B / s e c$ , it will take
$\frac{4.5 \times 1024 M B}{12 M B / s e c} = 384 s e c$ .
Now he has $4$ hours from $5$ PM to $9$ PM.
$1$ hour is equal to $3600$ secs.
Hence, he will upload $\frac{4 \times 3600 s e c}{384 s e c} = 37.5$ videos, or more clearly $37$ videos.
Therefore in a day he can upload a maximum of $37$ videos.

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Raj can upload n videos of approximately 4.5 gigabytes in size each on cloud between 5:00 PM and 9:00 PM daily, with speed of 12 megabytes per second. What is the maximum value of n per day? (1 gigabyte =1024 megabytes)

Raj can upload $n$ videos of approximately $4.5$ gigabytes in size each on cloud between $5 : 00$ PM and $9 : 00$ PM daily, with speed of $12$ megabytes per second. What is the maximum value of $n$ per day? ( $1$ gigabyte $= 1024$ megabytes)