Question

Raj takes $2\frac{1}{2}$ hours to complete his homework. However, Seema takes $\raisebox{1ex}{$8$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$ hours to complete her homework.Who takes less time and by how much $?$

Answer 1

step 1:-

Raju takes $2\frac{1}{2}$ hours to complete his work

it means Raju takes $2$ hours $30$ minutes

Seema takes $\raisebox{1ex}{$8$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$ hours to complete his work

$\raisebox{1ex}{$8$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$this can also written as $2\frac{2}{3}$

it means Seema takes $2$ hours $40$ minutes

From the above two conclusion it is clear that Raj takes less time

Difference between their time

$$\begin{gathered} =\raisebox{1ex}{$8$}\!\left/ \!\raisebox{-1ex}{$3-{\displaystyle \raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$}\right. \\ =\raisebox{1ex}{$16-15$}\!\left/ \!\raisebox{-1ex}{$6$}\right. \\ =\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$6$}\right. \end{gathered}$$

that is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$6$}\right.$ hours

$$\begin{gathered} =\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$6$}\right.\times 60 \\ =10 \end{gathered}$$

Raj takes $10$ minutes less time than Seema