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Question

Rajesh, Mahesh and Suresh divide a work amongst themselves in the ratio 2 : 3 : 5. Their rates of doing the work are in the ratio 1 : 2: 3. It takes Rajesh 12 days to complete his part . What is the amount of work completed by them in 8 days from the start ?

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Solution

The correct option is **A**

Proportion of work done by Rajesh , Mahesh and Suresh is 210,310 and 510 respectively.

Rate of doing work are in the ratio – 1:2:3

∴ The time required to complete the work are in the ratio - 1 : 12:13

Let, Rajesh complete the entire work in ‘x’ days.

∴ Work done by Rajesh in 1 day = 1x

According to Question,

(1x)×12=210

⇒ x = 60 days.

Thus, Mahesh and Suresh will complete the work in 30 and 20 days respectively.

∴ Total work done by three of them in 8 days = (160+260+360)×8=45

Proportion of work done by Rajesh , Mahesh and Suresh is 210,310 and 510 respectively.

Rate of doing work are in the ratio – 1:2:3

∴ The time required to complete the work are in the ratio - 1 : 12:13

Let, Rajesh complete the entire work in ‘x’ days.

∴ Work done by Rajesh in 1 day = 1x

According to Question,

(1x)×12=210

⇒ x = 60 days.

Thus, Mahesh and Suresh will complete the work in 30 and 20 days respectively.

∴ Total work done by three of them in 8 days = (160+260+360)×8=45

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