Ram has a LED of resistance 10 Ω which will only light up if the current provided is 1A. Below 1A current it won’t light up, above that the LED will burst. He also has 10 two volt cells. Find out how many cells will Ram need to light up the LED?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
5

Ohm’s Law states that, V=IR. So to light up the LED we need I = 1 and R = 10 so the potential across the LED will be

V=IR =1 x 10= 10V Since he has 2 volt cells so he will need 5 such cells to make a 10 volt battery.

Suggest Corrections

Similar questions

Ram has an LED of resistance 10 Ω which will only light up if the current provided is 1A. Below 1A current it won't light up, above that the LED will burst. He also has 10 two volt cells. Find out how many cells will Ram need to light up the LED?

Tina has a LED of resistance 10 Ω which will only light up if the current provided is 1A. Below 1A current it won't light up, above that the LED will burst. She also has 10 two volt cells. Find out how many cells will Ram need to light up the LED?

Ram has an LED of resistance 10 Ω which will only light up if the current provided is exactly 1A. He also has 10 two volt cells. Find out how many cells will Ram need to light up the LED?

If the speed of light is equal to $3 \times 10^{8} m s^{- 1}$ , how many kilometers will make up 1 light year?

Q. A 12-volt battery is connected to two light bulbs, as drawn in figure 1 light bulb 1 has resistance 3 ohms, while light bulb 2 has resistance 6 ohms. The battery has essentially no internal resistance, and all the wires are essentially resistanceless, too. When a light bulb is unscrewed, no current flows through that branch of the circuit. For instance, if light bulb 2 is unscrewed, current flows only around the lower loop of the circuit, which consist of the battery and light bulb 1. The more current flows through a light bulb, their equivalent resistance is

R_{e q} = R_{1} + R_{2}

. By contrast, when two reisistors are wired in parallel, their net resisance is given by

\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

Bulb 2 is now screwed in as a result, bulb 1 :

Join BYJU'S Learning Program

Ram has a LED of resistance 10 Ω which will only light up if the current provided is 1A. Below 1A current it won’t light up, above that the LED will burst. He also has 10 two volt cells. Find out how many cells will Ram need to light up the LED?

The correct option is C 5 Ohm’s Law states that, V=IR. So to light up the LED we need I = 1 and R = 10 so the potential across the LED will be V=IR =1 x 10= 10V Since he has 2 volt cells so he will need 5 such cells to make a 10 volt battery.

The correct option is C
5

Ohm’s Law states that, V=IR. So to light up the LED we need I = 1 and R = 10 so the potential across the LED will be

V=IR =1 x 10= 10V Since he has 2 volt cells so he will need 5 such cells to make a 10 volt battery.