Ram is standing $165 m$ behind Shyam. Shyam is standing ' $d$ ' meters away from a wall in the same line. Ram claps and Shyam hears the clap two times at an interval of $2$ seconds. Find the value of ' $d$ '. (Assume velocity of sound to be $330 m s^{- 1}$ )

165 m

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660 m

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330 m

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82.5 m

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Solution

The correct option is C $330 m$
The first sound heard by Shyam is direct sound and second sound is the reflection of the sound from the wall. The time gap between two sounds is the time taken by the sound to go to the wall and come back after reflection. So sound travels twice the distance ' $d$ ' in $2$ seconds.
Hence, $2 d = 2 \times 330 = 660 m$ .
Thus, $d = 330 m$ .

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