Ram is standing on the edge of a cliff $30 m$ . He throws ball vertically up with a velocity of $10 m / s$ at (time) $t = 0$ . The ball strikes the ground after the flight and does not rebound. Match the time intervals in column-I with description of motion in column-II

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Solution

$u = 10 m / s$ vertically up the velocity of ball becomes zero when
$v = u + a t$
$v = 0$
then $u - g t = 0$ this gives $t = 1 s$
Therefore, for $0 < t < 1$ ball is above the edge of cliff and its speed is decreasing.
$A \to 1, 3$
Now after $t = 1 s$ the ball reaches again the edge of cliff at
$t = 2 s$ in same interval of time.
Therefore,for $1 < t < 2$ Ball is above edge of cliff and its speed is increasing
$B \to 2, 3$
Now after $2 s$ speed of ball will increase but it is below the edge of cliff.
Therefore, for $2 < t < 2.5 s$ ball is below the edge of cliff and speed of ball is increasing.
$C \to 2, 4$
At $t = 2 s$
$v = u - g t = 10 - 10 \times 2 = - 10 m / s$
Therefore, speed of ball is $10 m / s$ and it is increasing and particle is at the edge of cliff
$D \to 2, 5$

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Ram is standing on the edge of a cliff 30m. He throws ball vertically up with a velocity of 10m/s at (time) t=0. The ball strikes the ground after the flight and does not rebound. Match the time intervals in column-I with description of motion in column-II

Ram is standing on the edge of a cliff $30 m$ . He throws ball vertically up with a velocity of $10 m / s$ at (time) $t = 0$ . The ball strikes the ground after the flight and does not rebound. Match the time intervals in column-I with description of motion in column-II