Ram is visiting a friend. Ram knows that his friend has $2$ children and $1$ of them is a boy. Assuming that a child is equally likely to be a boy or a girl, then the probability that the other child is a girl, is

\frac{1}{2}

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\frac{1}{3}

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\frac{2}{3}

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\frac{7}{10}

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Solution

The correct option is B $\frac{2}{3}$
Total sample space $= {B_{1} B_{2}, B_{1} G_{2}, G_{1} B_{2}}$

Favourable ways $= {B_{1} G_{2}, G_{1} B_{2}}$

$∴$ Required probability $= \frac{2}{3}$

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Ram is visiting a friend. Ram knows that his friend has 2 children and 1 of them is a boy. Assuming that a child is equally likely to be a boy or a girl, then the probability that the other child is a girl, is

The correct option is B 23Total sample space ={B1B2,B1G2,G1B2}Favourable ways ={B1G2,G1B2}∴ Required probability =23

Ram is visiting a friend. Ram knows that his friend has $2$ children and $1$ of them is a boy. Assuming that a child is equally likely to be a boy or a girl, then the probability that the other child is a girl, is

The correct option is B $\frac{2}{3}$
Total sample space $= {B_{1} B_{2}, B_{1} G_{2}, G_{1} B_{2}}$

Favourable ways $= {B_{1} G_{2}, G_{1} B_{2}}$

$∴$ Required probability $= \frac{2}{3}$