Ram prasad saved $R s . 10$ in the first week of the year and then increased his weekly saving by $R s . 2.75$ . If in the $n^{t h}$ week, his savings become $R s . 59.50$ , find $n$ .

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Solution

$a = 10, d = 2.75$
$a_{n} = a + (n - 1) d$
$59.50 = 10 + (n - 1) 2.75$
$(n - 1) 2.75 = 49.50$
$n - 1 = 18$
$n = 19$

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Ram prasad saved Rs.10 in the first week of the year and then increased his weekly saving by Rs.2.75. If in the nth week, his savings become Rs.59.50, find n.

a=10,d=2.75an=a+(n−1)d59.50=10+(n−1)2.75(n−1)2.75=49.50n−1=18n=19

Ram prasad saved $R s . 10$ in the first week of the year and then increased his weekly saving by $R s . 2.75$ . If in the $n^{t h}$ week, his savings become $R s . 59.50$ , find $n$ .

$a = 10, d = 2.75$
$a_{n} = a + (n - 1) d$
$59.50 = 10 + (n - 1) 2.75$
$(n - 1) 2.75 = 49.50$
$n - 1 = 18$
$n = 19$