Question

Ramesh and mahesh solve an equation. In solving Ramesh commits a mistake in constant term and finds the root 8 and 2. Mahesh commits a mistake in the coefficient of x and finds the roots -9 and -1 . Find the correct roots.

Answer 1

Take correct sum = $8+2=10$ from Ramesh
Take correct product = $-9$ $\times$ -1 = $9$ from Mahesh
$\therefore x^2$ - Sx + P = 0 or $x^2$ - 1$0x+9=0$
$\therefore$ Correct roots are $9,1.$