Question

Ramu says that the area of $△PQR$ is, $A=\frac{1}{2}\times 7\times 5c{m}^2$
Gopi says that it is, $A=\frac{1}{2}\times 8\times 5c{m}^2$. Who is correct? Why?

Answer 1

Ramu in $△PQR,PR$ is the base, because $QS\perp PR$.