Rana multiplied 987 by a certain number and obtained 559981 as his answer. If by mistake, both the 9s were written in place of two other digits, then the correct answer is:

553681

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555181

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555681

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556581

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Solution

The correct option is C 555681
$987 = 3 \times 7 \times 47$
So, the options should be divisible by all the three of them.
553681 and 555181 are not divisible by 3 (sum of digits = 28, 25 respectively)
Although 556581 is divisible by 3 it is not divisible by 7
And, 555681 is divisible by all the three (3, 7, 47).

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Rana multiplied 987 by a certain number and obtained 559981 as his answer. If by mistake, both the 9s were written in place of two other digits, then the correct answer is:

The correct option is C 555681987=3×7×47 So, the options should be divisible by all the three of them. 553681 and 555181 are not divisible by 3 (sum of digits = 28, 25 respectively) Although 556581 is divisible by 3 it is not divisible by 7 And, 555681 is divisible by all the three (3, 7, 47).