Rana travels $10 k m$ North turns left and travels $4 k m$ and then again turns right and covers another $5 k m .$ He then turns to right-hand side and travels another $4 k m .$ How far is he from the point of starting his journey?

15 k m

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4 k m

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5 k m

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10 k m

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Solution

The correct option is A $15 k m$
Let us consider a Cartesian plane thinking positive $X$ -axis as East; negative one as West; positive $Y$ -axis as North; negative as South.
Rana moves along $Y$ axis $10 k m$ and then parallel to $X$ axis $4 k m .$
After that $5 k m$ parallel to $Y$ axis and again $4 k m$ parallel to $X$ axis towards positive direction.
Hence, finally it will be on $Y$ axis at a distance of $15 k m$ from the origin that is from the starting place.

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Rana travels 10 km North turns left and travels 4 km and then again turns right and covers another 5 km. He then turns to right-hand side and travels another 4 km. How far is he from the point of starting his journey?

Rana travels $10 k m$ North turns left and travels $4 k m$ and then again turns right and covers another $5 k m .$ He then turns to right-hand side and travels another $4 k m .$ How far is he from the point of starting his journey?