Ranbir borrows Rs $20, 000$ at $12 %$ p.q C.I.F he repays $8400$ at the end of the first year and Rs $9680$ at the end of the $2^{n d}$ year the amount of loar outstanding at the begininig of the therd year.

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Solution

No. of year $n = 2, r = 12$ %, $P = R s .20, 000$

Total remaining Debt of first year $= P + P (1 + \frac{r}{100})^{n} - 8400$

$= 20000 + 20000 (1 + 0.12)^{1} - 8400$

$= R s .34000$

For second year,
Total remaining Debt of first year $= P + P (1 + \frac{r}{100})^{n} - 8400$

$= 34000 + 34000 (1 + 0.12)^{1} - 9680$

$= R s .62400$

Hence, total outstanding amount is $= R s .62400$ at the begining of the third year.

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Ranbir borrows Rs 20,000 at 12% p.q C.I.F he repays 8400 at the end of the first year and Rs 9680 at the end of the 2nd year the amount of loar outstanding at the begininig of the therd year.

Ranbir borrows Rs $20, 000$ at $12 %$ p.q C.I.F he repays $8400$ at the end of the first year and Rs $9680$ at the end of the $2^{n d}$ year the amount of loar outstanding at the begininig of the therd year.