You visited us 3 times! Enjoying our articles? Unlock Full Access!

Using Monotonicity to Find the Range of a Function

Range of f x ...

Question

Range of $f (x) = \frac{t a n (π [x^{2} - x])}{1 + s i n (c o s x)}$ is (where [x] denotes the greatest integer function)

(- \infty, \infty) \sim [0, t a n 1]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- \infty, \infty) \sim [t a n 2, 0]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[t a n 2, t a n 1]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{0}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D ${0}$
$f (x) = \frac{t a n (π [x^{2} - x])}{1 + s i n (c o s x)} = {0}$ because of $[x^{2} - x]$ is integer

Suggest Corrections

Similar questions

f (x) = \frac{t a n (π [x^{2} - x])}{1 + s i n (c o s x)}

[x]

[{cot}^{- 1} x] + 2 [{tan}^{- 1} x] = 0

[.]

f (x) = {\begin{matrix} \frac{tan [x] - [x] tan 1}{x} & ; x \neq 0 0 & ; x = 0 \end{matrix}

f^{'} (0^{-})

[

[x]

x]

f (x) = \frac{tan π [x]}{1 + sin π [x] + [x^{2}]}

f (x) = \frac{tan (π [x^{2} - x])}{1 + sin (cos x)}

Join BYJU'S Learning Program