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B
[−1,1)
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C
(−1,1)
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D
(−1,1]
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Solution
The correct option is B[−1,1) Let y=x2−1x2+1⇒(y−1)x2+(y+1)=0 ⇒y≠1 because coefficient of x2 can not be 0. x∈R⇒Δ≥0⇒−4(y−1)(y+1)≥0⇒(y2−1)≤0 ⇒y∈[−1,1] ∴Range of y=[−1,1)