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Question

Range of the function f(x)=sin20x+cos48x is

A
[0,1]
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B
(0,1]
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C
(0,)
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D
(,0)
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Solution

The correct option is B (0,1]
If 0a1 then a2a, so we use that repetadly

A=sin20x+cos48xsin2x+cos2x=1

So Amax=1 and it is achieved at x=0

Therefore the range of function is,

(0,1]

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