Range of x satisfying the inequality [sin−1x]>[cos−1x] is
([.] represents the Greatest Integer function)
A
[sin1,1]
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B
(cos1,1]
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C
[0,cos1)
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D
(sin1,1)
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Solution
The correct option is A[sin1,1] We know, [sin−1x]=−2,−1,0,1;[cos−1x]=0,1,2,3
So, [sin−1x]>[cos−1x] is possible only when [sin−1x]=1 and [cos−1x]=0 ⇒1≤sin−1x<2 and 0≤cos−1x<1 ⇒sin1≤x≤1 and cos1<x≤1 ∴x∈[sin1,1]