Rank the following bonds in order of increasing polarity: $C - O, C - N, N - N$

C - O < C - N < N - N

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N - N < C - O < C - N

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N - N < C - N < C - O

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C - O < N - N < C - N

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Solution

The correct option is C $N - N < C - N < C - O$
$N - N$ is non-polar as both are identical $C - O$ is more polar than $C - N$ due to more electronegativity of oxygen than nitrogen.

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The van der waals radii of $O, N, C l, F$ and $N e$ increases in the order of:

The Van der Waals radii of $O, N, C l, F$ and $N e$ increases in the order?

The Van der walls radii of $O, N, C l, F$ and $N e$ increases in the order.

A. F, O, Ne, Cl
B. N, O, F, Ne, Cl
C.Ne, F, O, N, Cl
D. F, Cl, O, N, Ne

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

Q. Find

A, B

and

C

in the following reactions:

$N H_{3} + A + C O_{2} \to {(N H_{4})}_{2} C O_{3}$

${(N H_{4})}_{2} C O_{3} + H_{2} O + B \to N H_{4} H C O_{3}$

$N H_{4} H C O_{3} + N a C l \to N H_{4} C l + C$

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Rank the following bonds in order of increasing polarity: C−O,C−N,N−N

The correct option is C N−N<C−N<C−ON−N is non-polar as both are identical C−O is more polar than C−N due to more electronegativity of oxygen than nitrogen.

Rank the following bonds in order of increasing polarity: $C - O, C - N, N - N$

The correct option is C $N - N < C - N < C - O$
$N - N$ is non-polar as both are identical $C - O$ is more polar than $C - N$ due to more electronegativity of oxygen than nitrogen.