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Question

Rank the following intermediates according to the stability (most stable first) :
CH3CH2CH2CH2,CH3CHCH2CH3,(CH3)2CCH2CH3,(CH3)3C

A
(CH3)2CCH2CH3>(CH3)3C>CH3CHCH2CH3>CH3CH2CH2CH2
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B
(CH3)3C>(CH3)2CCH2CH3>CH3CHCH2CH3>CH3CH2CH2CH2
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C
(CH3)3C>CH3CHCH2CH3>(CH3)2CCH2CH3>CH3CH2CH2CH2
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D
(CH3)3C>(CH3)2CCH2CH3>CH3CH2CH2CH2>CH3CHCH2CH3
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Solution

The correct option is B (CH3)3C>(CH3)2CCH2CH3>CH3CHCH2CH3>CH3CH2CH2CH2
Hyperconjugation or no bond resonance stabilize the carbocation. Higher the number of conjugated hydrogen atoms, higher will be the stability. Tertiary carbocation has 3 methyl groups with 9 hyperconjugative hydrogens which makes it most stable.
The order of stability is (CH3)3C+>(CH3)2C+CH2CH3>CH3C+HCH2CH3>CH3CH2CH2C+H2

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