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Organic Compounds

Rank the foll...

Question

Rank the following solvents in decreasing order of ability to dissolve given compound.

E t_{2} O > H_{2} O > E t O H

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H_{2} O > E t O H > E t_{2} O

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H_{2} O > E t_{2} O > E t O H

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E t_{2} O > E t O H > H_{2} O

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Solution

The correct option is D $E t_{2} O > E t O H > H_{2} O$
The extent of intermolecular hydrogen bonding will be maximum in water followed by $E t O H$ and then by $E t_{2} O$ . This is because there are $2$ hydrogen atoms directly attached to oxygen, whereas $E t O H$ has $1$ and $E t_{2} O$ has zero such hydrogens. The number of such hydrogen results in more hydrogen bonding. As the intermolecular hydrogen bonding increases, the ability to dissolve in the non-polar solvent decreases, due to the more association between solute molecules than solute and solvent molecules.
Hence, the order of ability to dissolve in a given non-polar solvent is- $E t_{2} O > E t O H > H_{2} O$

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