The correct option is C b>c>a
We need to figure out the corresponding conjugate bases to compare the acidity. Upon removing Hb, the conjugate base is an allyl anion. Hence, it is the most stable carbanion. The conjugate base upon removing Ha is an sp3 configured carboanion while the conjugate base upon removing Hc is an sp2 configured carbanion. sp3 has 25% s character & sp2 has 33%. Therefore, sp2 carbanion is more acidic. Thus , the acidity order is, Hb>Hc>Ha