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Question

Rank the transition states that occur during the following reaction steps in order of increasing stability (least→moststable)
1.H3C−+OH2→CH+3+H2O
2.(CH3)3C−+OH2→−(CH3)3C+H2O
3.(CH3)2CH−+OH2→(CH3)2CH++H2O

A
1 < 2 < 3
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B
2 < 3 < 1
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C
1 < 3 < 2
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D
2 < 1 < 3
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Solution

The correct option is C 1 < 3 < 2
(1) (Refer to Image 1)
(2) (Refer to Image 2)
(3) (Refer to Image 3)
Now stability of carbocations: tertiary > secondary > primary. Therefore transition state corresponding to tertiary carbocation will be most stable. So stability order will be 1<3<2.

1116707_989065_ans_e1e8a98cac6e49f19703835d6194e4a9.png

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