Rank the transition states that occur during the following reaction steps in order of increasing stability least most stable1- H3C - -OH2 CH3- - H2O2- CH33C - -OH2 - CH33C - H2O3- CH32 CH - -OH2CH32CH- - H2O

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Standard XII

Chemistry

State (Phase) of Alkanes

Rank the tran...

Question

Rank the transition states that occur during the following reaction steps in order of increasing stability $(l e a s t \to m o s t s t a b l e)$
1. $H_{3} C - + O H_{2} \to C H_{3}^{+} + H_{2} O$
2. $(C H_{3})_{3} C - + O H_{2} \to - (C H_{3})_{3} C + H_{2} O$
3. $(C H_{3})_{2} C H - + O H_{2} \to (C H_{3})_{2} C H^{+} + H_{2} O$

1 < 2 < 3

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2 < 3 < 1

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1 < 3 < 2

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2 < 1 < 3

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Solution

The correct option is C 1 < 3 < 2
(1) (Refer to Image 1)
(2) (Refer to Image 2)
(3) (Refer to Image 3)
Now stability of carbocations: tertiary $>$ secondary $>$ primary. Therefore transition state corresponding to tertiary carbocation will be most stable. So stability order will be $1 < 3 < 2$ .

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Q. Rank the transition states that occur during the following reaction steps in order of increasing stability (least

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(C H_{3})_{2} C - + O H_{2} \to (C H_{3})_{2} C H^{+} + H_{2} O

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Rank the transition states that occur during the following reaction steps in order of increasing stability (least→moststable)1.H3C−+OH2→CH+3+H2O2.(CH3)3C−+OH2→−(CH3)3C+H2O3.(CH3)2CH−+OH2→(CH3)2CH++H2O

The correct option is C 1 < 3 < 2(1) (Refer to Image 1)(2) (Refer to Image 2)(3) (Refer to Image 3)Now stability of carbocations: tertiary > secondary > primary. Therefore transition state corresponding to tertiary carbocation will be most stable. So stability order will be 1<3<2.

The correct option is C 1 < 3 < 2
(1) (Refer to Image 1)
(2) (Refer to Image 2)
(3) (Refer to Image 3)
Now stability of carbocations: tertiary $>$ secondary $>$ primary. Therefore transition state corresponding to tertiary carbocation will be most stable. So stability order will be $1 < 3 < 2$ .